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Question: Answered & Verified by Expert

In the given figure the magnetic flux through the loop increases according to the relation ϕB(t)=10t2+20t, where ϕB is in milliwebers and t is in seconds. The magnitude of current through R=2 Ω resistor at t=5 s is _____ mA.

PhysicsElectromagnetic InductionJEE MainJEE Main 2021 (27 Jul Shift 2)
Solution:
1436 Upvotes Verified Answer
The correct answer is: 60

|ϵ|=dϕdt=20t+20 mV

|i|=|ϵ|R=10t+10 mA

At t=5

|i|=60 mA

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