In the given potentiometer circuit arrangement, the balancing length AC is measured to be 250 cm . When the galvanometer connection is shifted from point (1) to point (2) in the given diagram, the balancing length becomes 400 cm . The ratio of the emf of two cells ε 1 ε 2 is:

Question

In the given potentiometer circuit arrangement, the balancing length AC is measured to be 250 cm . When the galvanometer connection is shifted from point (1) to point (2) in the given diagram, the balancing length becomes 400 cm . The ratio of the emf of two cells ε 1 ε 2 is:, 5 3, 8 5, 4 3, 3 2

MARKS App · Accepted Answer

E 1 = k ℓ 1 … ( 1 ) E 1 + E 2 = k ℓ 2 … ( 2 ) E 1 E 1 + E 2 = ℓ 1 ℓ 2 = 250 400 = 5 8 8 E 1 = 5 E 1 + 5 E 2 3 E 1 = 5 E 2 E 1 E 2 = 5 3

Search any question & find its solution

Looking for more such questions to practice?