In the given reaction C 6 H 5 CH 2 COOH → ii P 2 O 5 i NH 3 / Δ X X will be

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In the given reaction

C_{6} H_{5} {CH}_{2} COOH \to_{(ii) P_{2} O_{5}}^{(i) {NH}_{3} / Δ} (X)

(X)

will be

ChemistryCarboxylic Acid DerivativesNEET

Options:

A $C_{6} H_{5} - C H_{2} C O O N H_{4}$
B $C_{6} H_{5} - C H_{2} C O N H_{2}$
C $C_{6} H_{5} - C H_{2} - C N$
D $C_{6} H_{5} C N$

Solution:

2601 Upvotes Verified Answer

The correct answer is:

C_{6} H_{5} - C H_{2} - C N

Here X is benzyl cyanide and prepared as follows

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