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In the given reactions, ' $\mathrm{X}$ ' and ' $\mathrm{Y}$ ' respectively are
$\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_2 \mathrm{NH}_2 \stackrel{\mathrm{X}}{\longleftrightarrow} \mathrm{C}_6 \mathrm{H}_5 \mathrm{CONH}_2 \stackrel{\mathrm{Y}}{\longrightarrow} \mathrm{C}_6 \mathrm{H}_5 \mathrm{NH}_2$
Options:
$\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_2 \mathrm{NH}_2 \stackrel{\mathrm{X}}{\longleftrightarrow} \mathrm{C}_6 \mathrm{H}_5 \mathrm{CONH}_2 \stackrel{\mathrm{Y}}{\longrightarrow} \mathrm{C}_6 \mathrm{H}_5 \mathrm{NH}_2$
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Verified Answer
The correct answer is:
$\mathrm{LiAlH}_4, \mathrm{H}_2 \mathrm{O} ; \mathrm{Br}_2 / \mathrm{OH}^{-}$
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