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In the hardening stage of plaster of paris, the compound formed is
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Verified Answer
The correct answer is:
$Monoclinic$ $\mathrm{CaSO}_4 \cdot 2 \mathrm{H}_2 \mathrm{O}$
Plaster of paris absorb water to form monoclinic gypsum which is a hard substance.
$$
\mathrm{CaSO}_4 \cdot \frac{1}{2} \mathrm{H}_2 \mathrm{O} \stackrel{3 / 2 \mathrm{H}_2 \mathrm{O}}{\longrightarrow} \mathrm{CaSO}_4 \cdot 2 \mathrm{H}_2 \mathrm{O}
$$
(monoclinic gypsum)
$$
\mathrm{CaSO}_4 \cdot \frac{1}{2} \mathrm{H}_2 \mathrm{O} \stackrel{3 / 2 \mathrm{H}_2 \mathrm{O}}{\longrightarrow} \mathrm{CaSO}_4 \cdot 2 \mathrm{H}_2 \mathrm{O}
$$
(monoclinic gypsum)
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