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In the hydrocarbon
$$
\underset{8}{\mathrm{CH}_3}-\mathrm{CH}=\underset{4}{\mathrm{CH}}=\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{C} \equiv \mathrm{CH}_1
$$
The state of hybridization of carbons 1,3 and 5 are in the following sequence
Options:
$$
\underset{8}{\mathrm{CH}_3}-\mathrm{CH}=\underset{4}{\mathrm{CH}}=\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{C} \equiv \mathrm{CH}_1
$$
The state of hybridization of carbons 1,3 and 5 are in the following sequence
Solution:
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Verified Answer
The correct answer is:
$\mathrm{sp}, \mathrm{sp}^3, \mathrm{sp}_3^2$
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