In the ideal double-slit experiment, when a glass-plate (refractive index 1.5) of thickness t is introduced in the path of one of the interfering beams (wavelength λ ), the intensity at the position where the central maximum occurred previously remains unchanged. The minimum thickness of the glass-plate is

Question

In the ideal double-slit experiment, when a glass-plate (refractive index 1.5) of thickness t is introduced in the path of one of the interfering beams (wavelength λ ), the intensity at the position where the central maximum occurred previously remains unchanged. The minimum thickness of the glass-plate is, 2 λ, 2 λ 3, λ 3, λ

MARKS App · Accepted Answer

For no change of Intensity at central maxima there should again be maxima. ∴ Path difference due to slab should be integral multiple of λ or Δ x = n λ or μ - 1 t = λ n = 1 , 2 , 3 ,........ or t = n λ μ - 1 For minimum value of t , n = 1 t = λ μ - 1 = λ 1 · 5 - 1 = 2 λ

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