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In the ionic equation, $\mathrm{BiO}_{3}^{-}+6 \mathrm{H}^{+}+x e^{-} \longrightarrow \mathrm{Bi}^{3+}+3 \mathrm{H}_{2} \mathrm{O}$ the value of $x$ is
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Verified Answer
The correct answer is:
2
For the following reaction,
$$
\mathrm{BiO}_{3}^{-}+6 \mathrm{H}^{+}+x e^{-} \longrightarrow \mathrm{Bi}^{3+}+3 \mathrm{H}_{2} \mathrm{O}
$$
On balancing charge on both sides
$$
-1+6+x(-1)=3+3 \times 0
$$
$$
\therefore \quad x=2
$$
$$
\mathrm{BiO}_{3}^{-}+6 \mathrm{H}^{+}+x e^{-} \longrightarrow \mathrm{Bi}^{3+}+3 \mathrm{H}_{2} \mathrm{O}
$$
On balancing charge on both sides
$$
-1+6+x(-1)=3+3 \times 0
$$
$$
\therefore \quad x=2
$$
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