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Question: Answered & Verified by Expert
In the line spectra of hydrogen atom, difference between the largest and the shortest wavelengths of the Lyman series is 305 A. The corresponding difference for the Paschan series in A is:________
PhysicsAtomic PhysicsJEE MainJEE Main 2020 (04 Sep Shift 1)
Solution:
2655 Upvotes Verified Answer
The correct answer is: 10553.14

1λmin=R1=R;n= to 1

1λmax=R114=3R4 ; n=2 to 1

 λmaxλmin=43R1R

304=13R                                              ......a

Paschen : Yλ'min=R19

and Yλ'max=R19116=7R16×9

λ'maxλ'min=16×97R9R=817R       ...b

ba=x3×304=817

 x=10553.14

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