Search any question & find its solution
Question:
Answered & Verified by Expert
In the magnetic meridian of a certain place, the horizontal component of the earth's magnetic field is $86.6 \mathrm{G}$ (Gauss) and the magnetic field of earth is $100 \mathrm{G}$ (Gauss). Then the dip angle is
Options:
Solution:
1623 Upvotes
Verified Answer
The correct answer is:
$30^{\circ}$
Let $\phi$ be angle of dip
Then, $\cos \phi=\frac{\mathrm{B}_{\mathrm{H}}}{\mathrm{B}}=\frac{86.6}{100}=0.866=\frac{\sqrt{3}}{2}$
So, $\phi=30^{\circ}$
Then, $\cos \phi=\frac{\mathrm{B}_{\mathrm{H}}}{\mathrm{B}}=\frac{86.6}{100}=0.866=\frac{\sqrt{3}}{2}$
So, $\phi=30^{\circ}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.