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In the nuclear decay given below :
$$
{ }_{\mathrm{A}}^{\mathrm{A}} \mathrm{X} \longrightarrow \stackrel{\mathrm{A}}{\mathrm{A}+1} \mathrm{Y} \longrightarrow \mathrm{A}_{\mathrm{A}-4} \mathrm{~B}^* \longrightarrow \stackrel{\mathrm{A}-4}{\mathrm{Z}-1} \mathrm{~B}
$$
The particles emitted in the sequence are :
Options:
$$
{ }_{\mathrm{A}}^{\mathrm{A}} \mathrm{X} \longrightarrow \stackrel{\mathrm{A}}{\mathrm{A}+1} \mathrm{Y} \longrightarrow \mathrm{A}_{\mathrm{A}-4} \mathrm{~B}^* \longrightarrow \stackrel{\mathrm{A}-4}{\mathrm{Z}-1} \mathrm{~B}
$$
The particles emitted in the sequence are :
Solution:
2158 Upvotes
Verified Answer
The correct answer is:
$\beta, \alpha, \gamma$
$$
\begin{aligned}
& \mathrm{Z}^{\mathrm{X}^{\mathrm{A}} \stackrel{\beta}{\longrightarrow}} \mathrm{Z+1} \mathrm{Y}^{\mathrm{A}} \stackrel{\alpha}{\longrightarrow} \mathrm{Z}_{-1} \mathrm{~B}^{\mathrm{A}-4} \stackrel{\gamma}{\longrightarrow} \\
& \mathrm{Z}-1 \mathrm{~B}^{\mathrm{A}-4} \\
&
\end{aligned}
$$
\begin{aligned}
& \mathrm{Z}^{\mathrm{X}^{\mathrm{A}} \stackrel{\beta}{\longrightarrow}} \mathrm{Z+1} \mathrm{Y}^{\mathrm{A}} \stackrel{\alpha}{\longrightarrow} \mathrm{Z}_{-1} \mathrm{~B}^{\mathrm{A}-4} \stackrel{\gamma}{\longrightarrow} \\
& \mathrm{Z}-1 \mathrm{~B}^{\mathrm{A}-4} \\
&
\end{aligned}
$$
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