In the nuclear reaction ${ }_7^{14} \mathrm{~N}+\mathrm{X} \rightarrow{ }_6^{14} \mathrm{C}+{ }_1^1 \mathrm{H}$ the $\mathrm{X}$ will be

Question

In the nuclear reaction ${ }_7^{14} \mathrm{~N}+\mathrm{X} \rightarrow{ }_6^{14} \mathrm{C}+{ }_1^1 \mathrm{H}$ the $\mathrm{X}$ will be, ${ }_{-1}^0 \mathrm{e}$, ${ }_1^1 \mathrm{H}$, ${ }_1^2 \mathrm{H}$, ${ }_0^1 \mathrm{n}$

MARKS App · Accepted Answer

$\text {Hints: } \mathrm{X} \rightarrow{ }_0^1 \mathrm{n}$

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