In the nuclear reaction 90 23 Th → 91 234 Pa + X . X is-, − 1 0 e, 1 0 e, H, 1 2 H

90 234 Th ⟶ 91 234 Pa + − 1 e 0

In the nuclear reaction 90 23 Th → 91 234 Pa + X . X is-

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In the nuclear reaction ${ }_{90}^{23} \mathrm{Th} \rightarrow{ }_{91}^{234} \mathrm{~Pa}+\mathrm{X} . \mathrm{X}$ is-

ChemistryStructure of AtomKVPYKVPY 2010 (SB/SX)

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Solution:

2061 Upvotes Verified Answer

The correct answer is: ${ }_{-1}^{0} \mathrm{e}$

${ }_{90}^{234} \mathrm{Th} \longrightarrow{ }_{91}^{234} \mathrm{~Pa}+_{-1} \mathrm{e}^{0}$

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