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In the octahedral crystal field, the correct order of splitting in $\mathrm{Cr}^{3+}$ complexes for $\mathrm{I}^{-}, \mathrm{H}_2 \mathrm{O}, \mathrm{NH}_3$ and $\mathrm{CN}^{-}$is
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The correct answer is:
$I^{-} < \mathrm{H}_2 \mathrm{O} < \mathrm{NH}_3 < \mathrm{CN}^{-}$
$\because$ Order of crystal field splitting for the ligands
in $\mathrm{Cr}^{3+}$ is
Hence, correct order is $\mathrm{I}^{-} < \mathrm{H}_2 \mathrm{O} < \mathrm{NH}_3 < \mathrm{CN}^{-}$and option (d) is the correct answer.
in $\mathrm{Cr}^{3+}$ is
Hence, correct order is $\mathrm{I}^{-} < \mathrm{H}_2 \mathrm{O} < \mathrm{NH}_3 < \mathrm{CN}^{-}$and option (d) is the correct answer.
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