In the part of the circuit shown in the figure, the potential difference between points V A - V B = 16 V . The current passing through the 2 Ω resistance will be

Question

In the part of the circuit shown in the figure, the potential difference between points V A - V B = 16 V . The current passing through the 2 Ω resistance will be, 2 . 5 A, 3 . 5 A, 4 . 0 A, zero

MARKS App · Accepted Answer

V A - V B = 16 V ∴ 4 i 1 + 2 i 1 + i 2 - 3 + 4 i 1 = 16 V ......(i) Using Kirchhoff's second law in the closed loops we have ⇒ 9 - i 2 - 2 i 1 + i 2 = 0 ......(ii) Solving equations (i) and (ii), we get i 1 = 1 . 5 A and i 2 = 2 A ∴ Current through 2 Ω resistor = 2 + 1 . 5 = 3 . 5 A

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