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In the previous problem (3), the magnitude of the momentum transferred during the hit is
Options:
Solution:
1379 Upvotes
Verified Answer
The correct answer is:
$1.5 \mathrm{~kg}-\mathrm{m} \mathrm{s}^{-1}$
$1.5 \mathrm{~kg}-\mathrm{m} \mathrm{s}^{-1}$
From previous solution
$$
\begin{aligned}
\Delta p=-(0.9 \hat{i}+1.2 \hat{j}) &=-0.9 \hat{i}-1.2 \hat{j} \\
\text { Magnitude of }|\Delta p| &=\sqrt{(-0.9)^2+(-1.2)^2} \\
&=\sqrt{0.81+1.44} \\
&=\sqrt{2.25}=1.5 \mathrm{~kg}-\mathrm{m} \mathrm{s}^{-1}
\end{aligned}
$$
Verifies the option (c).
$$
\begin{aligned}
\Delta p=-(0.9 \hat{i}+1.2 \hat{j}) &=-0.9 \hat{i}-1.2 \hat{j} \\
\text { Magnitude of }|\Delta p| &=\sqrt{(-0.9)^2+(-1.2)^2} \\
&=\sqrt{0.81+1.44} \\
&=\sqrt{2.25}=1.5 \mathrm{~kg}-\mathrm{m} \mathrm{s}^{-1}
\end{aligned}
$$
Verifies the option (c).
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