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In the radioactive disintegration series ${ }_{90}^{232} \mathrm{Th} \longrightarrow{ }_{82}^{208} \mathrm{~Pb}$, involving $\alpha$ and $\beta$ decay, the total number of $\alpha$ and $\beta$ particles emitted are
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$6 \alpha$ and $4 \beta$
no. of $\alpha$-particle $=\frac{232-208}{4}=6$
no. of $\beta$-particle $=4$
no. of $\beta$-particle $=4$
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