Search any question & find its solution
Question:
Answered & Verified by Expert
In the reaction
$2 \mathrm{Ag}+2 \mathrm{H}_2 \mathrm{SO}_4 \rightarrow \mathrm{Ag}_2 \mathrm{SO}_4+2 \mathrm{H}_2 \mathrm{O}+\mathrm{SO}_2$
$\mathrm{H}_2 \mathrm{SO}_4$ acts as
Options:
$2 \mathrm{Ag}+2 \mathrm{H}_2 \mathrm{SO}_4 \rightarrow \mathrm{Ag}_2 \mathrm{SO}_4+2 \mathrm{H}_2 \mathrm{O}+\mathrm{SO}_2$
$\mathrm{H}_2 \mathrm{SO}_4$ acts as
Solution:
2693 Upvotes
Verified Answer
The correct answer is:
Oxidising agent
$\underset{\text { Reducing agent }}{2 \mathrm{Ag}}+\underset{\substack{\text { Oxidising } \\ \text { agent }}}{2 \mathrm{H}_2 \mathrm{SO}_4} \rightarrow \mathrm{Ag}_2 \mathrm{SO}_4+2 \mathrm{H}_2 \mathrm{O}+\mathrm{SO}_2$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.