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Question: Answered & Verified by Expert
In the reaction $2 \mathrm{PCl}_{5} \rightleftharpoons \mathrm{PCl}_{4}^{+}+\mathrm{PCl}_{6}^{-}$, the change in hybridisation is from
ChemistryChemical Bonding and Molecular StructureBITSATBITSAT 2020
Options:
  • A $s p^{3} d$ to $s p^{3}$ and $s p^{3} d^{2}$
  • B $s p^{3} d$ to $s p^{2}$ and $s p^{3}$
  • C $s p^{3} d$ to $s p^{3} d^{2}$ and $s p^{3} d^{3}$
  • D $s p^{3} d^{2}$ to $s p^{3}$ and $s p^{3} d$
Solution:
1417 Upvotes Verified Answer
The correct answer is: $s p^{3} d$ to $s p^{3}$ and $s p^{3} d^{2}$
$2 \mathrm{PCl}_{5} \rightleftharpoons \mathrm{PCl}_{4}^{+}+\mathrm{PCl}_{6}^{-}$

$\uparrow s p^{3} d \quad \uparrow s p^{3} \quad \uparrow s p^{3} d^{2}$

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