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In the reaction, $8 \mathrm{Al}+3 \mathrm{Fe}_{3} \mathrm{O}_{4} \longrightarrow 4 \mathrm{Al}_{2} \mathrm{O}_{3}+9 \mathrm{Fe}$ the number of electrons transferred from the reductant to the oxidant is
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Verified Answer
The correct answer is:
24
$\begin{array}{l}
8 \mathrm{Al} \longrightarrow 8 \mathrm{Al}^{3+}+24 \mathrm{e}^{-} \\
9 \mathrm{Fe}^{8 / 3+}+24 \mathrm{e}^{-} \longrightarrow 9 \mathrm{Fe}
\end{array}$
Total 24 electrons are transferred.
8 \mathrm{Al} \longrightarrow 8 \mathrm{Al}^{3+}+24 \mathrm{e}^{-} \\
9 \mathrm{Fe}^{8 / 3+}+24 \mathrm{e}^{-} \longrightarrow 9 \mathrm{Fe}
\end{array}$
Total 24 electrons are transferred.
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