Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
In the reaction,


$A$ is
ChemistryHydrocarbonsNEETNEET 2013 (All India)
Options:
  • A $\mathrm{HgSO}_4 / \mathrm{H}_2 \mathrm{SO}_4$
  • B $\mathrm{Cu}_2 \mathrm{Cl}_2$
  • C $\mathrm{H}_3 \mathrm{PO}_2$ and $\mathrm{H}_2 \mathrm{O}$
  • D $\mathrm{H}^{+} / \mathrm{H}_2 \mathrm{O}$
Solution:
1162 Upvotes Verified Answer
The correct answer is: $\mathrm{H}_3 \mathrm{PO}_2$ and $\mathrm{H}_2 \mathrm{O}$
When diazonium salt is treated with $\mathrm{H}_3 \mathrm{PO}_2$ followed by hydrolysis, it diazonium group is replaced by $-\mathrm{H}$ resulting to the formation of hydrocarbon. Thus, $A$ must be $\mathrm{H}_3 \mathrm{PO}_2 / \mathrm{H}_2 \mathrm{O}$.

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.