Search any question & find its solution
Question:
Answered & Verified by Expert
In the reaction
$$
\mathrm{BrO}_3^{-}(\mathrm{aq})+5 \mathrm{Br}^{-}(\mathrm{aq})+6 \mathrm{H}^{+} \rightarrow 3 \mathrm{Br}_2(l)+3 \mathrm{H}_2 \mathrm{O}(l)
$$
The rate of appearance of bromine $\left(\mathrm{Br}_2\right)$ is related to rate of disappearance of bromide ions as following
Options:
$$
\mathrm{BrO}_3^{-}(\mathrm{aq})+5 \mathrm{Br}^{-}(\mathrm{aq})+6 \mathrm{H}^{+} \rightarrow 3 \mathrm{Br}_2(l)+3 \mathrm{H}_2 \mathrm{O}(l)
$$
The rate of appearance of bromine $\left(\mathrm{Br}_2\right)$ is related to rate of disappearance of bromide ions as following
Solution:
1541 Upvotes
Verified Answer
The correct answer is:
$\frac{\mathrm{d}\left(\mathrm{Br}_2\right)}{\mathrm{dt}}=-\frac{3}{5} \frac{\mathrm{d}\left(\mathrm{Br}^{-}\right)}{\mathrm{dt}}$
$$
\begin{aligned}
& -\frac{1}{4} \frac{\mathrm{d}\left(\mathrm{Br}^{-}\right)}{\mathrm{dt}}=-\frac{1}{3} \frac{\mathrm{d}\left(\mathrm{Br}_2\right)}{\mathrm{dt}} \\
& \frac{\mathrm{d}\left(\mathrm{Br}_2\right)}{\mathrm{dt}}=-\frac{3}{5} \frac{\mathrm{d}\left(\mathrm{Br}^{-}\right)}{\mathrm{dt}}
\end{aligned}
$$
\begin{aligned}
& -\frac{1}{4} \frac{\mathrm{d}\left(\mathrm{Br}^{-}\right)}{\mathrm{dt}}=-\frac{1}{3} \frac{\mathrm{d}\left(\mathrm{Br}_2\right)}{\mathrm{dt}} \\
& \frac{\mathrm{d}\left(\mathrm{Br}_2\right)}{\mathrm{dt}}=-\frac{3}{5} \frac{\mathrm{d}\left(\mathrm{Br}^{-}\right)}{\mathrm{dt}}
\end{aligned}
$$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.