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In the reaction :
$$
\mathrm{C}_6 \mathrm{H}_5 \mathrm{CHO}+\mathrm{C}_6 \mathrm{H}_5 \mathrm{NH}_2 \rightarrow \mathrm{C}_6 \mathrm{H}_5 \mathrm{~N}=\mathrm{HCC}_6 \mathrm{H}_5+\mathrm{H}_2 \mathrm{O} \text {, }
$$
the compound $\mathrm{C}_6 \mathrm{H}_5 \mathrm{~N}=\mathrm{HCC}_6 \mathrm{H}_5$ is known as
Options:
$$
\mathrm{C}_6 \mathrm{H}_5 \mathrm{CHO}+\mathrm{C}_6 \mathrm{H}_5 \mathrm{NH}_2 \rightarrow \mathrm{C}_6 \mathrm{H}_5 \mathrm{~N}=\mathrm{HCC}_6 \mathrm{H}_5+\mathrm{H}_2 \mathrm{O} \text {, }
$$
the compound $\mathrm{C}_6 \mathrm{H}_5 \mathrm{~N}=\mathrm{HCC}_6 \mathrm{H}_5$ is known as
Solution:
2004 Upvotes
Verified Answer
The correct answer is:
Schiff's base
In the given reaction aldehyde $\left(\mathrm{C}_6 \mathrm{H}_5 \mathrm{CHO}\right)$ reacts with aniline $\left(\mathrm{C}_6 \mathrm{H}_5 \mathrm{NH}_2\right)$, they form amine $\left(\mathrm{C}_6 \mathrm{H}_5-\mathrm{N}=\mathrm{CHC}_6 \mathrm{H}_5\right)$ which is known as Schiff's base.
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