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In the reaction, $\mathrm{H}_2 \mathrm{C}=\mathrm{CH}_2 \xrightarrow{\substack{\text { coldalkaline } \\ \mathrm{KMnO}_4}}(A)$ :
Product A is :
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Product A is :
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Ethylene glycol
When ethylene is treated with cold alkaline $\mathrm{KMnO} 4$, ethylene glycol is formed.
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