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In the reaction,
$P, Q$ and $R$ respectively are
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$P, Q$ and $R$ respectively are
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Verified Answer
The correct answer is:
$\mathrm{NaNO}_2+$ dil. $\mathrm{HCl}, \mathrm{HBF}_4, \mathrm{Cu}+\mathrm{NaNO}_2$
Thus $P, Q$ and $R$ are $\mathrm{NaNO}_2+$ dil $\mathrm{HCl}, \mathrm{HBF}_4$, $\mathrm{Cu}+\mathrm{NaNO}_2$ respectively.
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