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In the reaction, $\mathrm{P}+\mathrm{Q} \longrightarrow ? \mathrm{R}+\mathrm{S}$
The time taken for $75 \%$ reaction of $P$ is twice the time taken for $50 \%$ reaction of $\mathrm{P}$. The concentration of $\mathrm{Q}$ varies with reaction time as shown in the figure. The overall order of the reaction is
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The time taken for $75 \%$ reaction of $P$ is twice the time taken for $50 \%$ reaction of $\mathrm{P}$. The concentration of $\mathrm{Q}$ varies with reaction time as shown in the figure. The overall order of the reaction is
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For $\mathrm{P}$, if $\mathrm{t}_{50 \%}=\mathrm{x}$ then $\mathrm{t}_{75 \%}=2 \mathrm{x}$
This is true only for first order reaction. So, order with respect to $\mathrm{P}$ is $1 .$ Further the graph shows that concentration of $\mathrm{Q}$ decreases with time. So rate, with respect to $\mathrm{Q},$ remains constant. Hence, it is zero order wrt Q. So, overall order is $1+0=1$
This is true only for first order reaction. So, order with respect to $\mathrm{P}$ is $1 .$ Further the graph shows that concentration of $\mathrm{Q}$ decreases with time. So rate, with respect to $\mathrm{Q},$ remains constant. Hence, it is zero order wrt Q. So, overall order is $1+0=1$
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