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In the reaction, product $P$ is
- A
- B
- C
- D
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The correct answer is:
$\mathrm{C}_6 \mathrm{H}_5 \mathrm{MgBr} \xrightarrow[\text { (i) } \mathrm{H}_3^{+} \mathrm{O}]{(\mathrm{z}) \mathrm{CO}_2} \mathrm{C}_6 \mathrm{H}_5 \mathrm{COOH}$
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