Search any question & find its solution
Question:
Answered & Verified by Expert
In the reversible reaction,
$2 \mathrm{NO}_{2} \frac{\mathrm{k}_{1}}{\rightleftharpoons \mathrm{k}_{2}} \mathrm{~N}_{2} \mathrm{O}_{4}$
the rate of disappearance of $\mathrm{NO}_{2}$ is equal to
Options:
$2 \mathrm{NO}_{2} \frac{\mathrm{k}_{1}}{\rightleftharpoons \mathrm{k}_{2}} \mathrm{~N}_{2} \mathrm{O}_{4}$
the rate of disappearance of $\mathrm{NO}_{2}$ is equal to
Solution:
2298 Upvotes
Verified Answer
The correct answer is:
$2 \mathrm{k}_{1}\left[\mathrm{NO}_{2}\right]^{2}-\mathrm{k}_{2}\left[\mathrm{~N}_{2} \mathrm{O}_{4}\right]$
$$
\begin{array}{l}
2 \mathrm{NO}_{2} \underset{\mathrm{k}_{2}}{\stackrel{\mathrm{k}_{1}}{\rightleftharpoons}} \mathrm{N}_{2} \mathrm{O}_{4} \\
\text { Rate }=-\frac{1}{2} \frac{\mathrm{d}\left[\mathrm{NO}_{2}\right]}{\mathrm{dt}}=k_{1}\left[\mathrm{NO}_{2}\right]^{2}-k_{2}\left[\mathrm{~N}_{2} \mathrm{O}_{4}\right]
\end{array}
$$
$\therefore$ Rate of disappearance of $\mathrm{NO}_{2}$ i.e.,
$$
-\frac{\mathrm{d}\left[\mathrm{NO}_{2}\right]}{\mathrm{dt}}=2 k_{1}\left[\mathrm{NO}_{2}\right]^{2}-k_{2}\left[\mathrm{~N}_{2} \mathrm{O}_{4}\right]
$$
\begin{array}{l}
2 \mathrm{NO}_{2} \underset{\mathrm{k}_{2}}{\stackrel{\mathrm{k}_{1}}{\rightleftharpoons}} \mathrm{N}_{2} \mathrm{O}_{4} \\
\text { Rate }=-\frac{1}{2} \frac{\mathrm{d}\left[\mathrm{NO}_{2}\right]}{\mathrm{dt}}=k_{1}\left[\mathrm{NO}_{2}\right]^{2}-k_{2}\left[\mathrm{~N}_{2} \mathrm{O}_{4}\right]
\end{array}
$$
$\therefore$ Rate of disappearance of $\mathrm{NO}_{2}$ i.e.,
$$
-\frac{\mathrm{d}\left[\mathrm{NO}_{2}\right]}{\mathrm{dt}}=2 k_{1}\left[\mathrm{NO}_{2}\right]^{2}-k_{2}\left[\mathrm{~N}_{2} \mathrm{O}_{4}\right]
$$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.