In the Rosenmund's reaction R C O C l + H 2 → P d / B a S O 4 R C H O + H C l Here, B a S O 4 is

Question

In the Rosenmund's reaction R C O C l + H 2 → P d / B a S O 4 R C H O + H C l Here, B a S O 4 is, Promotes catalytic activity of Pd, Removes the HCl formed in the reaction, Deactivates Pd, Activates Pd

MARKS App · Accepted Answer

R C O C l + H 2 → P d / B a S O 4 R C H O + H C l In this reaction, B a S O 4 decreases the activity of palladium.

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