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In the series $L-C-R$ circuit shown, the impedance is
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Verified Answer
The correct answer is:
$500 \Omega$
Here, $L=1 \mathrm{H}, C=20 \mu \mathrm{F}, R=300 \Omega$
$\begin{aligned}
& X_L=2 \pi f L=2 \pi\left(\frac{50}{\pi}\right) \times 1=100 \Omega \\
& X_C=\frac{1}{2 \pi f C}=\frac{1}{2 \pi\left(\frac{50}{\pi}\right) 20 \times 10^{-6}}=500 \Omega
\end{aligned}$
Impedance, $\begin{aligned} Z & =\sqrt{R^2+\left(X_C-X_L\right)^2} \\ & =\sqrt{(300)^2+(400)^2}=500 \Omega\end{aligned}$
$\begin{aligned}
& X_L=2 \pi f L=2 \pi\left(\frac{50}{\pi}\right) \times 1=100 \Omega \\
& X_C=\frac{1}{2 \pi f C}=\frac{1}{2 \pi\left(\frac{50}{\pi}\right) 20 \times 10^{-6}}=500 \Omega
\end{aligned}$
Impedance, $\begin{aligned} Z & =\sqrt{R^2+\left(X_C-X_L\right)^2} \\ & =\sqrt{(300)^2+(400)^2}=500 \Omega\end{aligned}$
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