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In the solid state, $\mathrm{PCl}_{5}$ exists as
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The correct answer is:
$\left[\mathrm{PCl}_{4}\right]^{+}$ and $\left[\mathrm{PCl}_{6}\right]^{-}$ ions
$\mathrm{PCl}_{5}$ exists as $\left[\mathrm{PCl}_{4}\right]^{+}$ and $\left[\mathrm{PCl}_{6}\right]^{-}$ in solid state.
$$
2 \mathrm{PCl}_{5} \longrightarrow\left[\mathrm{PCl}_{4}\right]^{+}\left[\mathrm{PCl}_{6}]^{-}\right.
$$
$$
2 \mathrm{PCl}_{5} \longrightarrow\left[\mathrm{PCl}_{4}\right]^{+}\left[\mathrm{PCl}_{6}]^{-}\right.
$$
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