In the triangle A B C , vertices A , B , C are 1 , 2 , 3,1 , - 1,6 respectively. If the internal angle bisector of ∠ B A C meets B C at D , then the coordinates of D are

Question

In the triangle A B C , vertices A , B , C are 1 , 2 , 3,1 , - 1,6 respectively. If the internal angle bisector of ∠ B A C meets B C at D , then the coordinates of D are, 5 3 , 8 3, 1 , 7 2, 1 3 , 13 3, 2 , 3 4

MARKS App · Accepted Answer

A B = 5 , A C = 20 = 2 5 Since A D is the internal angle bisector, so D divides B C in the ratio of A B : A C ≡ 1 : 2 Now, applying section formula, we get, The coordinates of D as 6 - 1 2 + 1 , 2 + 6 2 + 1 ≡ 5 3 , 8 3

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