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In thermodynamic process, 200 Joules of heat is given to a gas and 100 Joules of work is also done on it. The change in internal energy of the gas
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$300 \mathrm{~J}$
$\begin{aligned} & \Delta Q=\Delta U+\Delta W ; \Delta Q=200 \mathrm{~J} \text { and } \Delta W=-100 \mathrm{~J} \\ & \Rightarrow \Delta U=\Delta Q-\Delta W=200-(-100)=300 \mathrm{~J}\end{aligned}$
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