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Question: Answered & Verified by Expert
In transistor amplifier, base-emitter junction is forward biased and collector emitter junction is reverse biased. The current gain is
PhysicsSemiconductorsMHT CETMHT CET 2020 (14 Oct Shift 2)
Options:
  • A $\frac{\Delta \mathrm{I}_{\mathrm{E}}}{\Delta \mathrm{I}_{\mathrm{B}}}$
  • B $\frac{\Delta \mathrm{I}_{\mathrm{B}}}{\Delta \mathrm{I}_{\mathrm{E}}}$
  • C $\frac{\Delta \mathrm{I}_{\mathrm{B}}}{\Delta \mathrm{I}_{\mathrm{C}}}$
  • D $\frac{\Delta \mathrm{I}_{\mathrm{C}}}{\Delta \mathrm{I}_{\mathrm{B}}}$
Solution:
2756 Upvotes Verified Answer
The correct answer is: $\frac{\Delta \mathrm{I}_{\mathrm{C}}}{\Delta \mathrm{I}_{\mathrm{B}}}$
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