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In two separate experiments, the same quantity of electricity was passed through silver and gold solutions [Assume ' $t$ ' constant] The amounts of Ag and Au deposited are 2.15 and $1.31 \mathrm{~g}$, respectively. The valency of gold is $[$ Atomic mass of $\mathrm{Ag}=107.9 ; \mathrm{Au}=197]$
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$\begin{aligned} & \frac{\mathrm{m}_1}{\mathrm{~m}_2}=\frac{\mathrm{E}_1}{\mathrm{E}_2} \Rightarrow \frac{2.15}{1.31}=\frac{107.9}{\mathrm{E}_2} \\ & \mathrm{E}_2=65.7\end{aligned}$
Equivalent weight $=\frac{\text { Atomic mass }}{\text { Valency }}$
Valency of gold $=\frac{197}{65.7}=3$
Equivalent weight $=\frac{\text { Atomic mass }}{\text { Valency }}$
Valency of gold $=\frac{197}{65.7}=3$
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