In which case the number of molecules of water maximum?

Question

In which case the number of molecules of water maximum?, 0 . 00224 L of water vapours at 1 atm and 273 K ., 0 . 18 g of water., 18 mL of water., 10 - 3 mol of water.

MARKS App · Accepted Answer

(i) 18 mL water: As d H 2 O = 1 g / mL So W H 2 O = 18 g n H 2 O = 18 18 = 1 Molecules = 1 × N A (ii) 0 . 18 g of water: n H 2 O = 0 .18 18 = 0 .01 H 2 O molecules = 0 .01 × N A (iii) ( V H 2 O ( g ) ) STP = 0 .00224 L n H 2 O = V 22 .4 = 0 .00224 22 .4 = 0 .0001 Molecules = 0 .0001 × N A (iv) n H 2 O = 10 - 3 H 2 O molecules = 10 - 3 × N A

Search any question & find its solution

Looking for more such questions to practice?