Number of moleules $\propto$ Number of moles
(A) Moles of water $=\frac{0.00224}{22.4}=10^{-4}$
Molecules of water $=\mathrm{m}\mathrm{o}\mathrm{l}\mathrm{e}\times {\mathrm{N}}_{\mathrm{A}}=10^{-4}{\mathrm{N}}_{\mathrm{A}}$
(B) Molecules of water $=\mathrm{m}\mathrm{o}\mathrm{l}\mathrm{e}\times {\mathrm{N}}_{\mathrm{A}}=\frac{0.18}{18}{\mathrm{N}}_{\mathrm{A}}=10^{-2}{\mathrm{N}}_{\mathrm{A}}$
(C) Mass of water $=18\times 1=18\mathrm{g}$
Molecules of water $=\mathrm{m}\mathrm{o}\mathrm{l}\mathrm{e}\times {\mathrm{N}}_{\mathrm{A}}=\frac{18}{18}{\mathrm{N}}_{\mathrm{A}}={\mathrm{N}}_{\mathrm{A}}$
(D) Molecules of water $={10}^{-2}\text{mole}={10}^{-2}{\text{N}}_{\text{A}}$
Hence 18 ml ${\mathrm{H}}_2\mathrm{O}$ has maximum molecules.