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In which of the following chain termination step is absent?
Options:
- A Polymerisation of $\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}=\mathrm{CH}_2$ by $\mathrm{RLi}$
- B Polymerisation of $\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}=\mathrm{CH}_2$ by $\mathrm{BF}_3$ and $\mathrm{H}_2 \mathrm{O}$
- C
- D Polymerisation of $\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}=\mathrm{CH}_2$ by $\left(\mathrm{C}_6 \mathrm{H}_5 \mathrm{COO}\right)_2$
Solution:
1722 Upvotes
Verified Answer
The correct answer is:
In the polymerisation of $\mathrm{C}_6 \mathrm{H}_5-\mathrm{CH}=\mathrm{CH}_2$ by $\mathrm{RLi}$, free radicals like $\mathrm{C}_6 \mathrm{H}_5-\mathrm{CH}=\underset{\mathrm{R}}{\mathrm{CH}_2}$ and
are formed.
These radicals are very stable and thus the chain termination step is less favourable and does not occur.
are formed.
These radicals are very stable and thus the chain termination step is less favourable and does not occur.
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