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In which of the following complex ion, the central metal ion is in a state of $s p^{3} d^{2}$ hybridisation?
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Verified Answer
The correct answer is:
$\left[\mathrm{CoF}_{6}\right]^{3-}$
In $\left[\mathrm{CoF}_{6}\right]^{3-}, \mathrm{F}^{-}$is a weak ligand. It cannot pair up $d$-electrons and form outer orbital octahedral complex while $\mathrm{NH}_{3}$ and $\mathrm{CN}^{-}$are strong ligand.
In $\left[\mathrm{CoF}_{6}\right]^{3-}$, outer orbital $4 d$ is used in hybridisation. Thus, it is called outer orbital or high spin or spin free complex.
$$
\mathrm{Co}=[\mathrm{Ar}] 3 d^{7} 4 s^{2} \text { and } \mathrm{Co}^{3+}=[\mathrm{Ar}] 3 d^{6}
$$
In $\left[\mathrm{CoF}_{6}\right]^{3-}$, outer orbital $4 d$ is used in hybridisation. Thus, it is called outer orbital or high spin or spin free complex.
$$
\mathrm{Co}=[\mathrm{Ar}] 3 d^{7} 4 s^{2} \text { and } \mathrm{Co}^{3+}=[\mathrm{Ar}] 3 d^{6}
$$
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