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In which of the following equilibria, $\mathrm{K}_{\mathrm{p}}$ and $\mathrm{K}_{\mathrm{c}}$ are NOT equal?
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Verified Answer
The correct answer is:
$\mathrm{PCl}_{5(\mathrm{~g})} \rightleftharpoons \mathrm{PCl}_{3(\mathrm{~g})}+\mathrm{Cl}_{2(\mathrm{~g})}$
$\begin{aligned}
& \mathrm{K}_{\mathrm{p}}=\mathrm{K}_{\mathrm{c}}(\mathrm{RT})^{\Delta \mathrm{n}_{\mathrm{g}}} \\
& \text { for } \mathrm{K}_{\mathrm{p}} \neq \mathrm{K}_{\mathrm{c}} \\
& \qquad \Delta \mathrm{n}_{\mathrm{g}} \neq 0 \\
& \Delta \mathrm{n}_{\mathrm{g}}=\mathrm{n}_{\mathrm{p}}-\mathrm{n}_{\mathrm{r}}
\end{aligned}$
(1) $\Delta \mathrm{n}_{\mathrm{g}}=2-2=0$
(2) $\Delta \mathrm{ng}_{\mathrm{g}}=2-2=0$
(3) $\Delta \mathrm{ng}_{\mathrm{g}}=2-2=0$
(4) $\Delta \mathrm{ng}_{\mathrm{g}}=2-1=1$
& \mathrm{K}_{\mathrm{p}}=\mathrm{K}_{\mathrm{c}}(\mathrm{RT})^{\Delta \mathrm{n}_{\mathrm{g}}} \\
& \text { for } \mathrm{K}_{\mathrm{p}} \neq \mathrm{K}_{\mathrm{c}} \\
& \qquad \Delta \mathrm{n}_{\mathrm{g}} \neq 0 \\
& \Delta \mathrm{n}_{\mathrm{g}}=\mathrm{n}_{\mathrm{p}}-\mathrm{n}_{\mathrm{r}}
\end{aligned}$
(1) $\Delta \mathrm{n}_{\mathrm{g}}=2-2=0$
(2) $\Delta \mathrm{ng}_{\mathrm{g}}=2-2=0$
(3) $\Delta \mathrm{ng}_{\mathrm{g}}=2-2=0$
(4) $\Delta \mathrm{ng}_{\mathrm{g}}=2-1=1$
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