Search any question & find its solution
Question:
Answered & Verified by Expert
In which of the following plots, an endothermic reaction is correctly represented?
Options:
- A
- B
- C
- D
Solution:
2521 Upvotes
Verified Answer
The correct answer is:
$K_p$ and $T$ are related as follows :
$K_p=K_c \cdot(R T)^{\Delta z_g}$
where,
$\begin{aligned} & K_p=\text { Equilibrium constant in pressure terms } \\ & K_c=\text { Equilibrium constant in concentration terms. } \\ & \begin{aligned} R & =\text { Gas constant } \\ T & =\text { Temperature } \\ \Delta n_g & =\text { Gaseous moles of products } \\ & \quad-\text { gaseous moles of reactants }\end{aligned}\end{aligned}$
Therefore,
$K_p \propto T \quad$ (for another reaction)
Thus, the plot between $\frac{1}{T}$ and $\ln K_F$ shows a downward straight line slope for $\ln K_p$. Hence, option (d) is correct.
$K_p=K_c \cdot(R T)^{\Delta z_g}$
where,
$\begin{aligned} & K_p=\text { Equilibrium constant in pressure terms } \\ & K_c=\text { Equilibrium constant in concentration terms. } \\ & \begin{aligned} R & =\text { Gas constant } \\ T & =\text { Temperature } \\ \Delta n_g & =\text { Gaseous moles of products } \\ & \quad-\text { gaseous moles of reactants }\end{aligned}\end{aligned}$
Therefore,
$K_p \propto T \quad$ (for another reaction)
Thus, the plot between $\frac{1}{T}$ and $\ln K_F$ shows a downward straight line slope for $\ln K_p$. Hence, option (d) is correct.
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.