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In Williamson synthesis if tertiary alkyl halide is used than
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alkene is the only reaction product
If a tertiary alkyl halide is used, an alkene is the only reaction product and no ether is formed. For example, the reaction of $\mathrm{CH}_{3} \mathrm{ONa}$ with $\left(\mathrm{CH}_{3}\right)_{3} \mathrm{C}-\mathrm{Br}$ gives exclusively 2-methylpropene.
It is because alkoxides are not only nucleophiles but strong bases as well. They react with alkyl halides leading to elimination reactions.
It is because alkoxides are not only nucleophiles but strong bases as well. They react with alkyl halides leading to elimination reactions.
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