In X e O 3 and X e F 6 the oxidation state of X e is, + 4, + 6, + 1, + 3

The oxidation state of Xe in both XeO 3 and XeF 6 is +6

In X e O 3 and X e F 6 the oxidation state of X e is

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In $X e O_3$ and $X e F_6$ the oxidation state of $X e$ is

ChemistryRedox ReactionsJEE Main

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The correct answer is: $+6$

The oxidation state of $\mathrm{Xe}$ in both $\mathrm{XeO}_3$ and $\mathrm{XeF}_6$ is +6

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