In YDSE apparatus as shown in figure wavelength of light used in λ . The screen is moved away from the source with a constant speed V. Initial distance between screen and plane of slits was D . Suppose P is the point where 5 t h order maxima was lying at t = 0 , then after how much time third-order maxima will lie at this point P on that screen?

Question

In YDSE apparatus as shown in figure wavelength of light used in λ . The screen is moved away from the source with a constant speed V. Initial distance between screen and plane of slits was D . Suppose P is the point where 5 t h order maxima was lying at t = 0 , then after how much time third-order maxima will lie at this point P on that screen?, 2 D V, 2 D 3 V, 3 D 2 V, 3 D V

MARKS App · Accepted Answer

At t = 0 , Δ x = 5 λ = y d D .....(i) After t times Δ x 1 = 3 λ = y d D + v t ......(ii) Dividing (i) and (ii) we get 5 3 = D + v t D 5 D = 3 D + 3 v t 2 D = 3 v t ⇒ t = 2 D 3 v

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