In Young's double slit experiment, intensity at a point is 1 4 of the maximum intensity. Angular position of this point is

Question

In Young's double slit experiment, intensity at a point is 1 4 of the maximum intensity. Angular position of this point is, sin - 1 λ d, sin - 1 λ 2 d, sin - 1 λ 3 d, sin - 1 λ 4 d

MARKS App · Accepted Answer

I = I max cos 2 ϕ 2 I max 4 = I max cos 2 ϕ 2 cos ϕ 2 = 1 2 ϕ 2 = π 3 ⇒ ϕ = 2 π 3 = 2 π λ × Δ x . . . . i where, Δ x = d sin θ Putting the value of Δ x in Eq. (i), we get sin θ = λ 3 d θ = sin - 1 λ 3 d

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