Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
In Young's double slit experiment, slits are separated by 2 mm and the screen is placed at a distance of 1.2 m from the slits. Light consisting of two wavelengths 6500  and 5200 Å are used to obtain interference fringes. Then, the separation between the fourth bright fringes of two different patterns produced by the two wavelengths is
PhysicsWave OpticsNEET
Options:
  • A 0.312 mm
  • B 0. 123 mm
  • C 0.213 mm
  • D 0.412  mm
Solution:
2841 Upvotes Verified Answer
The correct answer is: 0.312 mm
y 4 = 4Dλ d

Separation between the fourth bright fringes

=4Dλ1d-4Dλ2d

4Ddλ1-λ2=4×1.22×10-36500-5200×10-10

=3120×10-7=0.312 mm

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.