In young's double slit experiment, the fringe width is 12 mm . If the entire arrangement is placed in water of refractive index 4 3 , then the fringe width becomes (in mm )

Question

In young's double slit experiment, the fringe width is 12 mm . If the entire arrangement is placed in water of refractive index 4 3 , then the fringe width becomes (in mm ), 16, 9, 48, 12

MARKS App · Accepted Answer

For a given light wavelength corresponding a medium of refractive index μ λ med = λ vacumm μ . And we know that fringe width β = λ D d Therefore, β med = β vacuum μ = 12 4 3 = 9 mm

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