Search any question & find its solution
Question:
Answered & Verified by Expert
In Young's double slit experiment with monochromatic light, fringes are obtained on a screen placed at some distance from the slits.
If the screen is moved by $5 \times 10^{-2} \mathrm{~m}$ towards the slits, the change in fringe width is $3 \times 10^{-5} \mathrm{~m}$. If the separation between the slits is $10^{-3} \mathrm{~m}$, the wavelength of light used is
Options:
If the screen is moved by $5 \times 10^{-2} \mathrm{~m}$ towards the slits, the change in fringe width is $3 \times 10^{-5} \mathrm{~m}$. If the separation between the slits is $10^{-3} \mathrm{~m}$, the wavelength of light used is
Solution:
1293 Upvotes
Verified Answer
The correct answer is:
$6000 Å$
$\begin{aligned} & \omega=\frac{\lambda D}{d} \\ & \Rightarrow \Delta \omega=\frac{\lambda(\Delta D)}{d} \\ & \therefore \lambda=\frac{(d)(\Delta \omega)}{\Delta D}=\frac{\left(\left(10^{-3}\right)\left(3 \times 10^{-5}\right)\right)}{5 \times 10^{-2}}=0.6 \times 10^{-6} \mathrm{~m}=6000 Å\end{aligned}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.