Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
In Young's double slits experiment, if the separation between the slits is halved, and the distance between the slits and the screen is doubled, then the fringe width compared to the original one will be
PhysicsWave OpticsNEET
Options:
  • A Unchanged
  • B Halved
  • C Doubled
  • D Quadrupled
Solution:
1048 Upvotes Verified Answer
The correct answer is: Quadrupled
The fringe width,

β=λDd

Where, λ= wavelength of light

d= distance of slit

D=  distance of screen from slit.

According to question,

d=d2

D=2D

β=?

β=λDd

=λ2Dd/2=4β

So, the fringe width will be quadrupled.

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.