In Young's double-slit experiment, the distance between slits and screen is 2 m and distance between slits is 0 . 25 mm . A light of wavelength 800 nm is used to find fringes on the screen. If the screen moves with a speed of 5 m s - 1 , then first maxima will move with a speed of:

Question

In Young's double-slit experiment, the distance between slits and screen is 2 m and distance between slits is 0 . 25 mm . A light of wavelength 800 nm is used to find fringes on the screen. If the screen moves with a speed of 5 m s - 1 , then first maxima will move with a speed of:, 16 mm s - 1, 8 mm s - 1, 20 mm s - 1, 50 mm s - 1

MARKS App · Accepted Answer

Given, D = 2 m , d = 0 . 25 mm = 2 . 5 × 10 - 4 m Velocity of screen, d D d t = 5 m s - 1 Speed of first maxima = d β d t = ? In Young's double-slit experiment, fringe width β = D λ d On differentiating with respect to t , we get d β d t = λ d · d D d t = 800 × 10 - 9 2 . 5 × 10 - 4 × 5 = 16 × 10 - 3 m s - 1 = 16 mm s - 1

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